x^2-4.84x+.03136=0

Solution for x^2-4.84x+.03136=0 equation:

x^2-4.84x+.03136=0

We add all the numbers together, and all the variables

x^2-4.84x+0.03136=0

a = 1; b = -4.84; c = +0.03136;
Δ = b2-4ac
Δ = -4.842-4·1·0.03136
Δ = 23.30016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.84)-\sqrt{23.30016}}{2*1}=\frac{4.84-\sqrt{23.30016}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.84)+\sqrt{23.30016}}{2*1}=\frac{4.84+\sqrt{23.30016}}{2}
$